32y^2-35=37

Solution for 32y^2-35=37 equation:

32y^2-35=37

We move all terms to the left:

32y^2-35-(37)=0

We add all the numbers together, and all the variables

32y^2-72=0

a = 32; b = 0; c = -72;
Δ = b2-4ac
Δ = 02-4·32·(-72)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*32}=\frac{-96}{64}
=-1+1/2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*32}=\frac{96}{64}
=1+1/2
$